Base | Representation |
---|---|
bin | 100010101000011010110111… |
… | …101010011011100010011111 |
3 | 201222021210212012212011200001 |
4 | 202220122313222123202133 |
5 | 124430431330132313002 |
6 | 1255534445445515131 |
7 | 44040056545224442 |
oct | 4250326752334237 |
9 | 658253765764601 |
10 | 152311211604127 |
11 | 44592905229484 |
12 | 150bab24712aa7 |
13 | 66cab68944564 |
14 | 2987c8b041659 |
15 | 1291e6e007a87 |
hex | 8a86b7a9b89f |
152311211604127 has 2 divisors, whose sum is σ = 152311211604128. Its totient is φ = 152311211604126.
The previous prime is 152311211604073. The next prime is 152311211604137. The reversal of 152311211604127 is 721406112113251.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 152311211604127 - 211 = 152311211602079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152311211604137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76155605802063 + 76155605802064.
It is an arithmetic number, because the mean of its divisors is an integer number (76155605802064).
Almost surely, 2152311211604127 is an apocalyptic number.
152311211604127 is a deficient number, since it is larger than the sum of its proper divisors (1).
152311211604127 is an equidigital number, since it uses as much as digits as its factorization.
152311211604127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 37.
Adding to 152311211604127 its reverse (721406112113251), we get a palindrome (873717323717378).
The spelling of 152311211604127 in words is "one hundred fifty-two trillion, three hundred eleven billion, two hundred eleven million, six hundred four thousand, one hundred twenty-seven".
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