Base | Representation |
---|---|
bin | 11100010111110011… |
… | …01000110001100011 |
3 | 1110022112210000101122 |
4 | 32023321220301203 |
5 | 222143400403011 |
6 | 10555243322455 |
7 | 1046315144633 |
oct | 161371506143 |
9 | 43275700348 |
10 | 15232044131 |
11 | 6507101227 |
12 | 2b5122042b |
13 | 1589942885 |
14 | a46d886c3 |
15 | 5e239d3db |
hex | 38be68c63 |
15232044131 has 2 divisors, whose sum is σ = 15232044132. Its totient is φ = 15232044130.
The previous prime is 15232044119. The next prime is 15232044167. The reversal of 15232044131 is 13144023251.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15232044131 - 210 = 15232043107 is a prime.
It is a super-2 number, since 2×152320441312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 15232044131.
It is not a weakly prime, because it can be changed into another prime (15232041131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7616022065 + 7616022066.
It is an arithmetic number, because the mean of its divisors is an integer number (7616022066).
Almost surely, 215232044131 is an apocalyptic number.
15232044131 is a deficient number, since it is larger than the sum of its proper divisors (1).
15232044131 is an equidigital number, since it uses as much as digits as its factorization.
15232044131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 15232044131 its reverse (13144023251), we get a palindrome (28376067382).
The spelling of 15232044131 in words is "fifteen billion, two hundred thirty-two million, forty-four thousand, one hundred thirty-one".
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