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152333150415133 is a prime number
BaseRepresentation
bin100010101000101111010011…
…010100010110100100011101
3201222100220111011121020121211
4202220233103110112210131
5124431311243001241013
61255552514434424421
744041464322104532
oct4250572324264435
9658326434536554
10152333150415133
11445a1143101946
1215103227a32111
1366ccc53bc132c
142988d6ca14d89
15129280509b23d
hex8a8bd351691d

152333150415133 has 2 divisors, whose sum is σ = 152333150415134. Its totient is φ = 152333150415132.

The previous prime is 152333150415053. The next prime is 152333150415157. The reversal of 152333150415133 is 331514051333251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117691297467844 + 34641852947289 = 10848562^2 + 5885733^2 .

It is a cyclic number.

It is not a de Polignac number, because 152333150415133 - 233 = 152324560480541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152333150415833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76166575207566 + 76166575207567.

It is an arithmetic number, because the mean of its divisors is an integer number (76166575207567).

Almost surely, 2152333150415133 is an apocalyptic number.

It is an amenable number.

152333150415133 is a deficient number, since it is larger than the sum of its proper divisors (1).

152333150415133 is an equidigital number, since it uses as much as digits as its factorization.

152333150415133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243000, while the sum is 40.

The spelling of 152333150415133 in words is "one hundred fifty-two trillion, three hundred thirty-three billion, one hundred fifty million, four hundred fifteen thousand, one hundred thirty-three".