1523659447361 has 2 divisors, whose sum is σ = 1523659447362. Its totient is φ = 1523659447360.

The previous prime is 1523659447351. The next prime is 1523659447363. The reversal of 1523659447361 is 1637449563251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1280787894961 + 242871552400 = 1131719^2 + 492820^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1523659447361 is a prime.

It is a super-2 number, since 2×1523659447361² (a number of 25 digits) contains 22 as substring.

Together with 1523659447363, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1523659447297 and 1523659447306.

It is not a weakly prime, because it can be changed into another prime (1523659447363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 761829723680 + 761829723681.

It is an arithmetic number, because the mean of its divisors is an integer number (761829723681).

Almost surely, 2^{1523659447361} is an apocalyptic number.

It is an amenable number.

1523659447361 is a deficient number, since it is larger than the sum of its proper divisors (1).

1523659447361 is an equidigital number, since it uses as much as digits as its factorization.

1523659447361 is an evil number, because the sum of its binary digits is even.

The product of its digits is 16329600, while the sum is 56.

The spelling of 1523659447361 in words is "one trillion, five hundred twenty-three billion, six hundred fifty-nine million, four hundred forty-seven thousand, three hundred sixty-one".