Base | Representation |
---|---|
bin | 1101110111000110101100… |
… | …0111101001000000101011 |
3 | 1222221221222120120212102022 |
4 | 3131301223013221000223 |
5 | 3444144204312200212 |
6 | 52225152134055055 |
7 | 3132035601123245 |
oct | 335615307510053 |
9 | 58857876525368 |
10 | 15240341131307 |
11 | 4946435287816 |
12 | 186181b4aa48b |
13 | 867209190746 |
14 | 3a98ca5a3095 |
15 | 1b6682506772 |
hex | ddc6b1e902b |
15240341131307 has 2 divisors, whose sum is σ = 15240341131308. Its totient is φ = 15240341131306.
The previous prime is 15240341131289. The next prime is 15240341131319. The reversal of 15240341131307 is 70313114304251.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 15240341131307 - 226 = 15240274022443 is a prime.
It is not a weakly prime, because it can be changed into another prime (15240341131357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7620170565653 + 7620170565654.
It is an arithmetic number, because the mean of its divisors is an integer number (7620170565654).
Almost surely, 215240341131307 is an apocalyptic number.
15240341131307 is a deficient number, since it is larger than the sum of its proper divisors (1).
15240341131307 is an equidigital number, since it uses as much as digits as its factorization.
15240341131307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30240, while the sum is 35.
Adding to 15240341131307 its reverse (70313114304251), we get a palindrome (85553455435558).
The spelling of 15240341131307 in words is "fifteen trillion, two hundred forty billion, three hundred forty-one million, one hundred thirty-one thousand, three hundred seven".
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