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15240341131319 is a prime number
BaseRepresentation
bin1101110111000110101100…
…0111101001000000110111
31222221221222120120212102202
43131301223013221000313
53444144204312200234
652225152134055115
73132035601123263
oct335615307510067
958857876525382
1015240341131319
114946435287827
12186181b4aa49b
13867209190755
143a98ca5a30a3
151b668250677e
hexddc6b1e9037

15240341131319 has 2 divisors, whose sum is σ = 15240341131320. Its totient is φ = 15240341131318.

The previous prime is 15240341131307. The next prime is 15240341131321. The reversal of 15240341131319 is 91313114304251.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15240341131319 is a prime.

It is a super-2 number, since 2×152403411313192 (a number of 27 digits) contains 22 as substring.

Together with 15240341131321, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15240341131369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7620170565659 + 7620170565660.

It is an arithmetic number, because the mean of its divisors is an integer number (7620170565660).

Almost surely, 215240341131319 is an apocalyptic number.

15240341131319 is a deficient number, since it is larger than the sum of its proper divisors (1).

15240341131319 is an equidigital number, since it uses as much as digits as its factorization.

15240341131319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 38.

The spelling of 15240341131319 in words is "fifteen trillion, two hundred forty billion, three hundred forty-one million, one hundred thirty-one thousand, three hundred nineteen".