Base | Representation |
---|---|
bin | 100010101010101011001111… |
… | …011111000111010000010110 |
3 | 201222211121222201112100220210 |
4 | 202222223033133013100112 |
5 | 124441001314402111202 |
6 | 1300134004050310250 |
7 | 44054215212633000 |
oct | 4252531737072026 |
9 | 658747881470823 |
10 | 152466230113302 |
11 | 44642624126876 |
12 | 15124b87b88386 |
13 | 670c671b33271 |
14 | 2991595111370 |
15 | 1295ee3497c6c |
hex | 8aaacf7c7416 |
152466230113302 has 32 divisors (see below), whose sum is σ = 355606367616000. Its totient is φ = 43561780031784.
The previous prime is 152466230113277. The next prime is 152466230113331. The reversal of 152466230113302 is 203311032664251.
It is a super-3 number, since 3×1524662301133023 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37042327902 + ... + 37042332017.
It is an arithmetic number, because the mean of its divisors is an integer number (11112698988000).
Almost surely, 2152466230113302 is an apocalyptic number.
152466230113302 is an abundant number, since it is smaller than the sum of its proper divisors (203140137502698).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
152466230113302 is an equidigital number, since it uses as much as digits as its factorization.
152466230113302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74084659945 (or 74084659931 counting only the distinct ones).
The product of its (nonzero) digits is 155520, while the sum is 39.
Adding to 152466230113302 its reverse (203311032664251), we get a palindrome (355777262777553).
The spelling of 152466230113302 in words is "one hundred fifty-two trillion, four hundred sixty-six billion, two hundred thirty million, one hundred thirteen thousand, three hundred two".
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