Base | Representation |
---|---|
bin | 1000111000001001111… |
… | …1011000111011101111 |
3 | 112120122220100100012022 |
4 | 2032002133120323233 |
5 | 4444321324401111 |
6 | 154021421300355 |
7 | 14006263101434 |
oct | 2160237307357 |
9 | 476586310168 |
10 | 152513122031 |
11 | 59753754a06 |
12 | 256844046bb |
13 | 114c712450a |
14 | 754b459b8b |
15 | 3e7954d2db |
hex | 23827d8eef |
152513122031 has 2 divisors, whose sum is σ = 152513122032. Its totient is φ = 152513122030.
The previous prime is 152513122001. The next prime is 152513122039. The reversal of 152513122031 is 130221315251.
It is a strong prime.
It is an emirp because it is prime and its reverse (130221315251) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-152513122031 is a prime.
It is a super-2 number, since 2×1525131220312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152513122039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76256561015 + 76256561016.
It is an arithmetic number, because the mean of its divisors is an integer number (76256561016).
Almost surely, 2152513122031 is an apocalyptic number.
152513122031 is a deficient number, since it is larger than the sum of its proper divisors (1).
152513122031 is an equidigital number, since it uses as much as digits as its factorization.
152513122031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 152513122031 its reverse (130221315251), we get a palindrome (282734437282).
The spelling of 152513122031 in words is "one hundred fifty-two billion, five hundred thirteen million, one hundred twenty-two thousand, thirty-one".
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