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15252016133 is a prime number
BaseRepresentation
bin11100011010001011…
…10100110000000101
31110100221100200211102
432031011310300011
5222214004004013
611001235345445
71046646666224
oct161505646005
943327320742
1015252016133
116517402512
122b57a52285
131590b16323
14a498a6cbb
155e3ee5d58
hex38d174c05

15252016133 has 2 divisors, whose sum is σ = 15252016134. Its totient is φ = 15252016132.

The previous prime is 15252016127. The next prime is 15252016147. The reversal of 15252016133 is 33161025251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8096040484 + 7155975649 = 89978^2 + 84593^2 .

It is an emirp because it is prime and its reverse (33161025251) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15252016133 - 224 = 15235238917 is a prime.

It is a super-2 number, since 2×152520161332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 15252016096 and 15252016105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15252016163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7626008066 + 7626008067.

It is an arithmetic number, because the mean of its divisors is an integer number (7626008067).

Almost surely, 215252016133 is an apocalyptic number.

It is an amenable number.

15252016133 is a deficient number, since it is larger than the sum of its proper divisors (1).

15252016133 is an equidigital number, since it uses as much as digits as its factorization.

15252016133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 29.

The spelling of 15252016133 in words is "fifteen billion, two hundred fifty-two million, sixteen thousand, one hundred thirty-three".