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15253052555197 is a prime number
BaseRepresentation
bin1101110111110110000011…
…0001110111111110111101
32000000011210110101002212201
43131331200301313332331
53444401222423231242
652235053340031501
73132665601341152
oct335754061677675
960004713332781
1015253052555197
114950868580716
121864188532591
13868483834342
143aa374890229
151b6b784544b7
hexddf60c77fbd

15253052555197 has 2 divisors, whose sum is σ = 15253052555198. Its totient is φ = 15253052555196.

The previous prime is 15253052555179. The next prime is 15253052555243. The reversal of 15253052555197 is 79155525035251.

Together with previous prime (15253052555179) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14660061691716 + 592990863481 = 3828846^2 + 770059^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15253052555197 is a prime.

It is a super-2 number, since 2×152530525551972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15253052855197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7626526277598 + 7626526277599.

It is an arithmetic number, because the mean of its divisors is an integer number (7626526277599).

Almost surely, 215253052555197 is an apocalyptic number.

It is an amenable number.

15253052555197 is a deficient number, since it is larger than the sum of its proper divisors (1).

15253052555197 is an equidigital number, since it uses as much as digits as its factorization.

15253052555197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11812500, while the sum is 55.

The spelling of 15253052555197 in words is "fifteen trillion, two hundred fifty-three billion, fifty-two million, five hundred fifty-five thousand, one hundred ninety-seven".