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152536542401 is a prime number
BaseRepresentation
bin1000111000001111100…
…0101110110011000001
3112120201112102012220102
42032003320232303001
54444343323324101
6154024015252145
714006666134415
oct2160370566301
9476645365812
10152536542401
11597659a0a91
122569021a055
13114cbc34719
1475505d4d45
153e7b62786b
hex2383e2ecc1

152536542401 has 2 divisors, whose sum is σ = 152536542402. Its totient is φ = 152536542400.

The previous prime is 152536542391. The next prime is 152536542419. The reversal of 152536542401 is 104245635251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 146918890000 + 5617652401 = 383300^2 + 74951^2 .

It is an emirp because it is prime and its reverse (104245635251) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152536542401 is a prime.

It is not a weakly prime, because it can be changed into another prime (152536542701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76268271200 + 76268271201.

It is an arithmetic number, because the mean of its divisors is an integer number (76268271201).

Almost surely, 2152536542401 is an apocalyptic number.

It is an amenable number.

152536542401 is a deficient number, since it is larger than the sum of its proper divisors (1).

152536542401 is an equidigital number, since it uses as much as digits as its factorization.

152536542401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144000, while the sum is 38.

The spelling of 152536542401 in words is "one hundred fifty-two billion, five hundred thirty-six million, five hundred forty-two thousand, four hundred one".