Base | Representation |
---|---|
bin | 1000111000010011100… |
… | …1001000010101001111 |
3 | 112120202201011220101111 |
4 | 2032010321020111033 |
5 | 4444412134033312 |
6 | 154025421152451 |
7 | 14010262465462 |
oct | 2160471102517 |
9 | 476681156344 |
10 | 152553424207 |
11 | 59774481598 |
12 | 256959bb727 |
13 | 11502595762 |
14 | 755294b2d9 |
15 | 3e7cd5e8a7 |
hex | 2384e4854f |
152553424207 has 2 divisors, whose sum is σ = 152553424208. Its totient is φ = 152553424206.
The previous prime is 152553424189. The next prime is 152553424213. The reversal of 152553424207 is 702424355251.
It is a strong prime.
It is an emirp because it is prime and its reverse (702424355251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 152553424207 - 215 = 152553391439 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 152553424207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152553424607) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76276712103 + 76276712104.
It is an arithmetic number, because the mean of its divisors is an integer number (76276712104).
Almost surely, 2152553424207 is an apocalyptic number.
152553424207 is a deficient number, since it is larger than the sum of its proper divisors (1).
152553424207 is an equidigital number, since it uses as much as digits as its factorization.
152553424207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336000, while the sum is 40.
Adding to 152553424207 its reverse (702424355251), we get a palindrome (854977779458).
The spelling of 152553424207 in words is "one hundred fifty-two billion, five hundred fifty-three million, four hundred twenty-four thousand, two hundred seven".
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