Base | Representation |
---|---|
bin | 100010110010011101100000… |
… | …100100110101101110110011 |
3 | 202001201202221111111120110021 |
4 | 202302131200210311232303 |
5 | 130023233020001133121 |
6 | 1301223444402344311 |
7 | 44140655236046452 |
oct | 4262354044655663 |
9 | 661652844446407 |
10 | 153001240255411 |
11 | 44829509432209 |
12 | 151b07b995b097 |
13 | 674ac55316152 |
14 | 29ad429d20b99 |
15 | 12a4da79b1641 |
hex | 8b2760935bb3 |
153001240255411 has 2 divisors, whose sum is σ = 153001240255412. Its totient is φ = 153001240255410.
The previous prime is 153001240255343. The next prime is 153001240255447. The reversal of 153001240255411 is 114552042100351.
153001240255411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 153001240255411 - 215 = 153001240222643 is a prime.
It is not a weakly prime, because it can be changed into another prime (153001240255711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76500620127705 + 76500620127706.
It is an arithmetic number, because the mean of its divisors is an integer number (76500620127706).
Almost surely, 2153001240255411 is an apocalyptic number.
153001240255411 is a deficient number, since it is larger than the sum of its proper divisors (1).
153001240255411 is an equidigital number, since it uses as much as digits as its factorization.
153001240255411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 153001240255411 its reverse (114552042100351), we get a palindrome (267553282355762).
The spelling of 153001240255411 in words is "one hundred fifty-three trillion, one billion, two hundred forty million, two hundred fifty-five thousand, four hundred eleven".
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