Base | Representation |
---|---|
bin | 1101111010100110011110… |
… | …1100111001001011110001 |
3 | 2000011201001010000202101011 |
4 | 3132221213230321023301 |
5 | 4001140221303031121 |
6 | 52312525101510521 |
7 | 3136263335313241 |
oct | 336514754711361 |
9 | 60151033022334 |
10 | 15300413330161 |
11 | 4969961497953 |
12 | 18713a5572441 |
13 | 86ca9087923b |
14 | 3ac78888bb21 |
15 | 1b7eeb26b7e1 |
hex | dea67b392f1 |
15300413330161 has 2 divisors, whose sum is σ = 15300413330162. Its totient is φ = 15300413330160.
The previous prime is 15300413330159. The next prime is 15300413330177. The reversal of 15300413330161 is 16103331400351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10285362126400 + 5015051203761 = 3207080^2 + 2239431^2 .
It is a cyclic number.
It is not a de Polignac number, because 15300413330161 - 21 = 15300413330159 is a prime.
Together with 15300413330159, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (15300413340161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7650206665080 + 7650206665081.
It is an arithmetic number, because the mean of its divisors is an integer number (7650206665081).
Almost surely, 215300413330161 is an apocalyptic number.
It is an amenable number.
15300413330161 is a deficient number, since it is larger than the sum of its proper divisors (1).
15300413330161 is an equidigital number, since it uses as much as digits as its factorization.
15300413330161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 31.
The spelling of 15300413330161 in words is "fifteen trillion, three hundred billion, four hundred thirteen million, three hundred thirty thousand, one hundred sixty-one".
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