Base | Representation |
---|---|
bin | 100010110010100000011101… |
… | …100010000011110100111110 |
3 | 202001202002010102201122110122 |
4 | 202302200131202003310332 |
5 | 130023311013031424132 |
6 | 1301225131130134542 |
7 | 44141126632026422 |
oct | 4262403542036476 |
9 | 661662112648418 |
10 | 153004410420542 |
11 | 4482a89595819a |
12 | 151b1343581452 |
13 | 674b33c039bc5 |
14 | 29ad64ad80b82 |
15 | 12a4ee0e69912 |
hex | 8b281d883d3e |
153004410420542 has 4 divisors (see below), whose sum is σ = 229506615630816. Its totient is φ = 76502205210270.
The previous prime is 153004410420539. The next prime is 153004410420583. The reversal of 153004410420542 is 245024014400351.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1530044104205422 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38251102605134 + ... + 38251102605137.
It is an arithmetic number, because the mean of its divisors is an integer number (57376653907704).
Almost surely, 2153004410420542 is an apocalyptic number.
153004410420542 is a deficient number, since it is larger than the sum of its proper divisors (76502205210274).
153004410420542 is an equidigital number, since it uses as much as digits as its factorization.
153004410420542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76502205210273.
The product of its (nonzero) digits is 76800, while the sum is 35.
Adding to 153004410420542 its reverse (245024014400351), we get a palindrome (398028424820893).
The spelling of 153004410420542 in words is "one hundred fifty-three trillion, four billion, four hundred ten million, four hundred twenty thousand, five hundred forty-two".
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