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153010150425443 is a prime number
BaseRepresentation
bin100010110010100101110011…
…101010011100001101100011
3202001202121221110120002220202
4202302211303222130031203
5130023404242002103233
61301231520454255415
744141422111203533
oct4262456352341543
9661677843502822
10153010150425443
1144832270a488a3
12151b248595756b
13674ba452a39cc
1429ada334314c3
1512a5229d46be8
hex8b2973a9c363

153010150425443 has 2 divisors, whose sum is σ = 153010150425444. Its totient is φ = 153010150425442.

The previous prime is 153010150425437. The next prime is 153010150425463. The reversal of 153010150425443 is 344524051010351.

153010150425443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 153010150425443 - 234 = 152992970556259 is a prime.

It is a super-2 number, since 2×1530101504254432 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 153010150425397 and 153010150425406.

It is not a weakly prime, because it can be changed into another prime (153010150425463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76505075212721 + 76505075212722.

It is an arithmetic number, because the mean of its divisors is an integer number (76505075212722).

Almost surely, 2153010150425443 is an apocalyptic number.

153010150425443 is a deficient number, since it is larger than the sum of its proper divisors (1).

153010150425443 is an equidigital number, since it uses as much as digits as its factorization.

153010150425443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144000, while the sum is 38.

The spelling of 153010150425443 in words is "one hundred fifty-three trillion, ten billion, one hundred fifty million, four hundred twenty-five thousand, four hundred forty-three".