Base | Representation |
---|---|
bin | 100010110010111000101010… |
… | …010011011001110011010011 |
3 | 202001211120012022022221021022 |
4 | 202302320222103121303103 |
5 | 130024222221442022341 |
6 | 1301245105342550055 |
7 | 44143036555654262 |
oct | 4262705223316323 |
9 | 661746168287238 |
10 | 153030394485971 |
11 | 4483a90a214132 |
12 | 151b639559832b |
13 | 67509203c1752 |
14 | 29b09d3cc85d9 |
15 | 12a5a12221e4b |
hex | 8b2e2a4d9cd3 |
153030394485971 has 2 divisors, whose sum is σ = 153030394485972. Its totient is φ = 153030394485970.
The previous prime is 153030394485919. The next prime is 153030394486019. The reversal of 153030394485971 is 179584493030351.
It is a happy number.
153030394485971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (179584493030351) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 153030394485971 - 218 = 153030394223827 is a prime.
It is not a weakly prime, because it can be changed into another prime (153030394415971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76515197242985 + 76515197242986.
It is an arithmetic number, because the mean of its divisors is an integer number (76515197242986).
Almost surely, 2153030394485971 is an apocalyptic number.
153030394485971 is a deficient number, since it is larger than the sum of its proper divisors (1).
153030394485971 is an equidigital number, since it uses as much as digits as its factorization.
153030394485971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48988800, while the sum is 62.
The spelling of 153030394485971 in words is "one hundred fifty-three trillion, thirty billion, three hundred ninety-four million, four hundred eighty-five thousand, nine hundred seventy-one".
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