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153030394485971 is a prime number
BaseRepresentation
bin100010110010111000101010…
…010011011001110011010011
3202001211120012022022221021022
4202302320222103121303103
5130024222221442022341
61301245105342550055
744143036555654262
oct4262705223316323
9661746168287238
10153030394485971
114483a90a214132
12151b639559832b
1367509203c1752
1429b09d3cc85d9
1512a5a12221e4b
hex8b2e2a4d9cd3

153030394485971 has 2 divisors, whose sum is σ = 153030394485972. Its totient is φ = 153030394485970.

The previous prime is 153030394485919. The next prime is 153030394486019. The reversal of 153030394485971 is 179584493030351.

It is a happy number.

153030394485971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (179584493030351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 153030394485971 - 218 = 153030394223827 is a prime.

It is not a weakly prime, because it can be changed into another prime (153030394415971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76515197242985 + 76515197242986.

It is an arithmetic number, because the mean of its divisors is an integer number (76515197242986).

Almost surely, 2153030394485971 is an apocalyptic number.

153030394485971 is a deficient number, since it is larger than the sum of its proper divisors (1).

153030394485971 is an equidigital number, since it uses as much as digits as its factorization.

153030394485971 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48988800, while the sum is 62.

The spelling of 153030394485971 in words is "one hundred fifty-three trillion, thirty billion, three hundred ninety-four million, four hundred eighty-five thousand, nine hundred seventy-one".