Base | Representation |
---|---|
bin | 1000111010000101110… |
… | …0101011100001011001 |
3 | 112122000002122202021121 |
4 | 2032201130223201121 |
5 | 10001402310133213 |
6 | 154145133405241 |
7 | 14025200555653 |
oct | 2164134534131 |
9 | 478002582247 |
10 | 153032505433 |
11 | 5999a950395 |
12 | 257aa339821 |
13 | 1157a905182 |
14 | 759a4196d3 |
15 | 3ea9e4488d |
hex | 23a172b859 |
153032505433 has 2 divisors, whose sum is σ = 153032505434. Its totient is φ = 153032505432.
The previous prime is 153032505403. The next prime is 153032505469. The reversal of 153032505433 is 334505230351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 152789519689 + 242985744 = 390883^2 + 15588^2 .
It is an emirp because it is prime and its reverse (334505230351) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 153032505433 - 221 = 153030408281 is a prime.
It is not a weakly prime, because it can be changed into another prime (153032505403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76516252716 + 76516252717.
It is an arithmetic number, because the mean of its divisors is an integer number (76516252717).
Almost surely, 2153032505433 is an apocalyptic number.
It is an amenable number.
153032505433 is a deficient number, since it is larger than the sum of its proper divisors (1).
153032505433 is an equidigital number, since it uses as much as digits as its factorization.
153032505433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 34.
Adding to 153032505433 its reverse (334505230351), we get a palindrome (487537735784).
The spelling of 153032505433 in words is "one hundred fifty-three billion, thirty-two million, five hundred five thousand, four hundred thirty-three".
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