Base | Representation |
---|---|
bin | 100010110010111011000101… |
… | …101100100000001001011011 |
3 | 202001211210220222221200220022 |
4 | 202302323011230200021123 |
5 | 130024243041343042133 |
6 | 1301250220153021055 |
7 | 44143161303341441 |
oct | 4262730554401133 |
9 | 661753828850808 |
10 | 153033001534043 |
11 | 44840a27892a14 |
12 | 151b69a26b478b |
13 | 6750c47561747 |
14 | 29b0ba0242b91 |
15 | 12a5b16045998 |
hex | 8b2ec5b2025b |
153033001534043 has 2 divisors, whose sum is σ = 153033001534044. Its totient is φ = 153033001534042.
The previous prime is 153033001534033. The next prime is 153033001534097. The reversal of 153033001534043 is 340435100330351.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-153033001534043 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 153033001533994 and 153033001534012.
It is not a weakly prime, because it can be changed into another prime (153033001534033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76516500767021 + 76516500767022.
It is an arithmetic number, because the mean of its divisors is an integer number (76516500767022).
Almost surely, 2153033001534043 is an apocalyptic number.
153033001534043 is a deficient number, since it is larger than the sum of its proper divisors (1).
153033001534043 is an equidigital number, since it uses as much as digits as its factorization.
153033001534043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 35.
Adding to 153033001534043 its reverse (340435100330351), we get a palindrome (493468101864394).
The spelling of 153033001534043 in words is "one hundred fifty-three trillion, thirty-three billion, one million, five hundred thirty-four thousand, forty-three".
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