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15311143243142 = 28053950648407
BaseRepresentation
bin1101111011001110011101…
…0000010000110110000110
32000012201201220020210212122
43132303213100100312012
54001324210132240032
652321501521045542
73140123255133335
oct336634720206606
960181656223778
1015311143243142
11497346822232a
12187349aa868b2
13870ab084a286
143ad0c5933d1c
151b842825a012
hexdece7410d86

15311143243142 has 8 divisors (see below), whose sum is σ = 22969566834096. Its totient is φ = 7654620965112.

The previous prime is 15311143243127. The next prime is 15311143243153. The reversal of 15311143243142 is 24134234111351.

15311143243142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×153111432431422 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 475308098 + ... + 475340309.

It is an arithmetic number, because the mean of its divisors is an integer number (2871195854262).

Almost surely, 215311143243142 is an apocalyptic number.

15311143243142 is a deficient number, since it is larger than the sum of its proper divisors (7658423590954).

15311143243142 is an equidigital number, since it uses as much as digits as its factorization.

15311143243142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 950656462.

The product of its digits is 34560, while the sum is 35.

Adding to 15311143243142 its reverse (24134234111351), we get a palindrome (39445377354493).

The spelling of 15311143243142 in words is "fifteen trillion, three hundred eleven billion, one hundred forty-three million, two hundred forty-three thousand, one hundred forty-two".

Divisors: 1 2 8053 16106 950648407 1901296814 7655571621571 15311143243142