Base | Representation |
---|---|
bin | 1101111011001110011101… |
… | …0000010000110110000110 |
3 | 2000012201201220020210212122 |
4 | 3132303213100100312012 |
5 | 4001324210132240032 |
6 | 52321501521045542 |
7 | 3140123255133335 |
oct | 336634720206606 |
9 | 60181656223778 |
10 | 15311143243142 |
11 | 497346822232a |
12 | 187349aa868b2 |
13 | 870ab084a286 |
14 | 3ad0c5933d1c |
15 | 1b842825a012 |
hex | dece7410d86 |
15311143243142 has 8 divisors (see below), whose sum is σ = 22969566834096. Its totient is φ = 7654620965112.
The previous prime is 15311143243127. The next prime is 15311143243153. The reversal of 15311143243142 is 24134234111351.
15311143243142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×153111432431422 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 475308098 + ... + 475340309.
It is an arithmetic number, because the mean of its divisors is an integer number (2871195854262).
Almost surely, 215311143243142 is an apocalyptic number.
15311143243142 is a deficient number, since it is larger than the sum of its proper divisors (7658423590954).
15311143243142 is an equidigital number, since it uses as much as digits as its factorization.
15311143243142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 950656462.
The product of its digits is 34560, while the sum is 35.
Adding to 15311143243142 its reverse (24134234111351), we get a palindrome (39445377354493).
The spelling of 15311143243142 in words is "fifteen trillion, three hundred eleven billion, one hundred forty-three million, two hundred forty-three thousand, one hundred forty-two".
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