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153121417 is a prime number
BaseRepresentation
bin10010010000001…
…11001010001001
3101200010101002121
421020013022021
5303144341132
623105531241
73536340061
oct1110071211
9350111077
10153121417
1179484429
1243343b21
13259528b7
141649c3a1
15d699497
hex9207289

153121417 has 2 divisors, whose sum is σ = 153121418. Its totient is φ = 153121416.

The previous prime is 153121403. The next prime is 153121447. The reversal of 153121417 is 714121351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86192656 + 66928761 = 9284^2 + 8181^2 .

It is a cyclic number.

It is not a de Polignac number, because 153121417 - 27 = 153121289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 153121391 and 153121400.

It is not a weakly prime, because it can be changed into another prime (153121447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76560708 + 76560709.

It is an arithmetic number, because the mean of its divisors is an integer number (76560709).

Almost surely, 2153121417 is an apocalyptic number.

It is an amenable number.

153121417 is a deficient number, since it is larger than the sum of its proper divisors (1).

153121417 is an equidigital number, since it uses as much as digits as its factorization.

153121417 is an evil number, because the sum of its binary digits is even.

The product of its digits is 840, while the sum is 25.

The square root of 153121417 is about 12374.2238948550. The cubic root of 153121417 is about 534.9895674444.

Adding to 153121417 its reverse (714121351), we get a palindrome (867242768).

The spelling of 153121417 in words is "one hundred fifty-three million, one hundred twenty-one thousand, four hundred seventeen".