Base | Representation |
---|---|
bin | 10110010010000011011… |
… | …111111010111101110111 |
3 | 12102101022222022002200012 |
4 | 112102003133322331313 |
5 | 200041411410300123 |
6 | 3131232533410435 |
7 | 215424631563203 |
oct | 26220337727567 |
9 | 5371288262605 |
10 | 1531214540663 |
11 | 540425764835 |
12 | 208914799a1b |
13 | b15152c4402 |
14 | 5417b10bb03 |
15 | 29c6c932378 |
hex | 164837faf77 |
1531214540663 has 2 divisors, whose sum is σ = 1531214540664. Its totient is φ = 1531214540662.
The previous prime is 1531214540659. The next prime is 1531214540693. The reversal of 1531214540663 is 3660454121351.
It is a weak prime.
It is an emirp because it is prime and its reverse (3660454121351) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1531214540663 - 22 = 1531214540659 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1531214540663.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1531214540623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765607270331 + 765607270332.
It is an arithmetic number, because the mean of its divisors is an integer number (765607270332).
Almost surely, 21531214540663 is an apocalyptic number.
1531214540663 is a deficient number, since it is larger than the sum of its proper divisors (1).
1531214540663 is an equidigital number, since it uses as much as digits as its factorization.
1531214540663 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 41.
The spelling of 1531214540663 in words is "one trillion, five hundred thirty-one billion, two hundred fourteen million, five hundred forty thousand, six hundred sixty-three".
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