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15312214453 is a prime number
BaseRepresentation
bin11100100001010110…
…11101100110110101
31110112010122002101211
432100223131212311
5222324411330303
611011225521421
71051310450434
oct162053354665
943463562354
1015312214453
116548389398
122b74043271
1315a0432633
14a5389711b
155e943766d
hex390add9b5

15312214453 has 2 divisors, whose sum is σ = 15312214454. Its totient is φ = 15312214452.

The previous prime is 15312214447. The next prime is 15312214523. The reversal of 15312214453 is 35441221351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8067991684 + 7244222769 = 89822^2 + 85113^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15312214453 is a prime.

It is a super-2 number, since 2×153122144532 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15312212453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7656107226 + 7656107227.

It is an arithmetic number, because the mean of its divisors is an integer number (7656107227).

Almost surely, 215312214453 is an apocalyptic number.

It is an amenable number.

15312214453 is a deficient number, since it is larger than the sum of its proper divisors (1).

15312214453 is an equidigital number, since it uses as much as digits as its factorization.

15312214453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14400, while the sum is 31.

The spelling of 15312214453 in words is "fifteen billion, three hundred twelve million, two hundred fourteen thousand, four hundred fifty-three".