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153124339217 is a prime number
BaseRepresentation
bin1000111010011011101…
…0111111111000010001
3112122020111110101112212
42032212322333320101
510002044312323332
6154202214001505
714030364256643
oct2164672777021
9478214411485
10153124339217
1159a37774483
1225815046295
13115939499a5
1475a86c2893
153eb30348b2
hex23a6ebfe11

153124339217 has 2 divisors, whose sum is σ = 153124339218. Its totient is φ = 153124339216.

The previous prime is 153124339163. The next prime is 153124339219. The reversal of 153124339217 is 712933421351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91717516801 + 61406822416 = 302849^2 + 247804^2 .

It is an emirp because it is prime and its reverse (712933421351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 153124339217 - 26 = 153124339153 is a prime.

Together with 153124339219, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (153124339219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76562169608 + 76562169609.

It is an arithmetic number, because the mean of its divisors is an integer number (76562169609).

Almost surely, 2153124339217 is an apocalyptic number.

It is an amenable number.

153124339217 is a deficient number, since it is larger than the sum of its proper divisors (1).

153124339217 is an equidigital number, since it uses as much as digits as its factorization.

153124339217 is an evil number, because the sum of its binary digits is even.

The product of its digits is 136080, while the sum is 41.

The spelling of 153124339217 in words is "one hundred fifty-three billion, one hundred twenty-four million, three hundred thirty-nine thousand, two hundred seventeen".