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1531318427 is a prime number
BaseRepresentation
bin101101101000110…
…0001000010011011
310221201110000222022
41123101201002123
511114004142202
6411541245055
752642664132
oct13321410233
93851400868
101531318427
11716431221
12368a0378b
131b53393a2
14107536919
158e683ea2
hex5b46109b

1531318427 has 2 divisors, whose sum is σ = 1531318428. Its totient is φ = 1531318426.

The previous prime is 1531318387. The next prime is 1531318429. The reversal of 1531318427 is 7248131351.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1531318427 is a prime.

It is a super-3 number, since 3×15313184273 (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1531318429, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1531318429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765659213 + 765659214.

It is an arithmetic number, because the mean of its divisors is an integer number (765659214).

Almost surely, 21531318427 is an apocalyptic number.

1531318427 is a deficient number, since it is larger than the sum of its proper divisors (1).

1531318427 is an equidigital number, since it uses as much as digits as its factorization.

1531318427 is an evil number, because the sum of its binary digits is even.

The product of its digits is 20160, while the sum is 35.

The square root of 1531318427 is about 39132.0639246130. The cubic root of 1531318427 is about 1152.6262416473.

Adding to 1531318427 its reverse (7248131351), we get a palindrome (8779449778).

The spelling of 1531318427 in words is "one billion, five hundred thirty-one million, three hundred eighteen thousand, four hundred twenty-seven".