Base | Representation |
---|---|
bin | 100010110100011011011001… |
… | …111101001000110001111111 |
3 | 202002012200212110021100021011 |
4 | 202310123121331020301333 |
5 | 130032441342141413312 |
6 | 1301405522255420051 |
7 | 44153512155350344 |
oct | 4264333175106177 |
9 | 662180773240234 |
10 | 153136420654207 |
11 | 44880878223661 |
12 | 15212a45524627 |
13 | 675a91952cac3 |
14 | 29b5bb140a7cb |
15 | 12a866a512da7 |
hex | 8b46d9f48c7f |
153136420654207 has 2 divisors, whose sum is σ = 153136420654208. Its totient is φ = 153136420654206.
The previous prime is 153136420654123. The next prime is 153136420654237. The reversal of 153136420654207 is 702456024631351.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 153136420654207 - 219 = 153136420129919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (153136420654237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76568210327103 + 76568210327104.
It is an arithmetic number, because the mean of its divisors is an integer number (76568210327104).
Almost surely, 2153136420654207 is an apocalyptic number.
153136420654207 is a deficient number, since it is larger than the sum of its proper divisors (1).
153136420654207 is an equidigital number, since it uses as much as digits as its factorization.
153136420654207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3628800, while the sum is 49.
The spelling of 153136420654207 in words is "one hundred fifty-three trillion, one hundred thirty-six billion, four hundred twenty million, six hundred fifty-four thousand, two hundred seven".
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