Base | Representation |
---|---|
bin | 1000111010100000011… |
… | …0111001100101110111 |
3 | 112122021212220021100211 |
4 | 2032220012321211313 |
5 | 10002114411031112 |
6 | 154204204250251 |
7 | 14031025350151 |
oct | 2165006714567 |
9 | 478255807324 |
10 | 153144236407 |
11 | 59a47a24538 |
12 | 2581b840987 |
13 | 11597ac5386 |
14 | 75ab1c1ad1 |
15 | 3eb4b650a7 |
hex | 23a81b9977 |
153144236407 has 2 divisors, whose sum is σ = 153144236408. Its totient is φ = 153144236406.
The previous prime is 153144236359. The next prime is 153144236477. The reversal of 153144236407 is 704632441351.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-153144236407 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 153144236407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (153144236477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76572118203 + 76572118204.
It is an arithmetic number, because the mean of its divisors is an integer number (76572118204).
Almost surely, 2153144236407 is an apocalyptic number.
153144236407 is a deficient number, since it is larger than the sum of its proper divisors (1).
153144236407 is an equidigital number, since it uses as much as digits as its factorization.
153144236407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 40.
Adding to 153144236407 its reverse (704632441351), we get a palindrome (857776677758).
The spelling of 153144236407 in words is "one hundred fifty-three billion, one hundred forty-four million, two hundred thirty-six thousand, four hundred seven".
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