Base | Representation |
---|---|
bin | 10110010011101111010… |
… | …100101101001111100101 |
3 | 12102120000001020210111221 |
4 | 112103233110231033211 |
5 | 200104113011241242 |
6 | 3132132234500341 |
7 | 215520516042262 |
oct | 26235724551745 |
9 | 5376001223457 |
10 | 1533023540197 |
11 | 541173905976 |
12 | 20913a5946b1 |
13 | b1743015836 |
14 | 542ad488269 |
15 | 29d26667167 |
hex | 164ef52d3e5 |
1533023540197 has 2 divisors, whose sum is σ = 1533023540198. Its totient is φ = 1533023540196.
The previous prime is 1533023540149. The next prime is 1533023540249. The reversal of 1533023540197 is 7910453203351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 838911278241 + 694112261956 = 915921^2 + 833134^2 .
It is a cyclic number.
It is not a de Polignac number, because 1533023540197 - 223 = 1533015151589 is a prime.
It is a super-2 number, since 2×15330235401972 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1533023540297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 766511770098 + 766511770099.
It is an arithmetic number, because the mean of its divisors is an integer number (766511770099).
Almost surely, 21533023540197 is an apocalyptic number.
It is an amenable number.
1533023540197 is a deficient number, since it is larger than the sum of its proper divisors (1).
1533023540197 is an equidigital number, since it uses as much as digits as its factorization.
1533023540197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 340200, while the sum is 43.
The spelling of 1533023540197 in words is "one trillion, five hundred thirty-three billion, twenty-three million, five hundred forty thousand, one hundred ninety-seven".
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