Base | Representation |
---|---|
bin | 10110010011110000011… |
… | …100110110011010000101 |
3 | 12102120001100211121202211 |
4 | 112103300130312122011 |
5 | 200104132331431401 |
6 | 3132134152103421 |
7 | 215521135560106 |
oct | 26236034663205 |
9 | 5376040747684 |
10 | 1533042452101 |
11 | 541183552746 |
12 | 209144994b71 |
13 | b1746c07904 |
14 | 542b1bac3ad |
15 | 29d28150951 |
hex | 164f0736685 |
1533042452101 has 2 divisors, whose sum is σ = 1533042452102. Its totient is φ = 1533042452100.
The previous prime is 1533042452027. The next prime is 1533042452147. The reversal of 1533042452101 is 1012542403351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1533015422500 + 27029601 = 1238150^2 + 5199^2 .
It is a cyclic number.
It is not a de Polignac number, because 1533042452101 - 217 = 1533042321029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1533042452191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 766521226050 + 766521226051.
It is an arithmetic number, because the mean of its divisors is an integer number (766521226051).
Almost surely, 21533042452101 is an apocalyptic number.
It is an amenable number.
1533042452101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1533042452101 is an equidigital number, since it uses as much as digits as its factorization.
1533042452101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1533042452101 its reverse (1012542403351), we get a palindrome (2545584855452).
The spelling of 1533042452101 in words is "one trillion, five hundred thirty-three billion, forty-two million, four hundred fifty-two thousand, one hundred one".
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