15331124131 has 2 divisors, whose sum is σ = 15331124132. Its totient is φ = 15331124130.

The previous prime is 15331124113. The next prime is 15331124167. The reversal of 15331124131 is 13142113351.

Together with previous prime (15331124113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15331124131 is a prime.

It is a super-2 number, since 2×15331124131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 15331124096 and 15331124105.

It is not a weakly prime, because it can be changed into another prime (15331224131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7665562065 + 7665562066.

It is an arithmetic number, because the mean of its divisors is an integer number (7665562066).

Almost surely, 2^15331124131 is an apocalyptic number.

15331124131 is a deficient number, since it is larger than the sum of its proper divisors (1).

15331124131 is an equidigital number, since it uses as much as digits as its factorization.

15331124131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1080, while the sum is 25.

Adding to 15331124131 its reverse (13142113351), we get a palindrome (28473237482).

The spelling of 15331124131 in words is "fifteen billion, three hundred thirty-one million, one hundred twenty-four thousand, one hundred thirty-one".