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153312215044231 is a prime number
BaseRepresentation
bin100010110110111111001000…
…000111100001000010000111
3202002211111121212102122012101
4202312333020013201002013
5130043331404022403411
61302022354223332531
744202304416123025
oct4266771007410207
9662744555378171
10153312215044231
1144939388607811
1215240b26751147
136771383a83029
1429c04ca84d715
1512ad0088ce8c1
hex8b6fc81e1087

153312215044231 has 2 divisors, whose sum is σ = 153312215044232. Its totient is φ = 153312215044230.

The previous prime is 153312215044181. The next prime is 153312215044237. The reversal of 153312215044231 is 132440512213351.

It is a strong prime.

It is an emirp because it is prime and its reverse (132440512213351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 153312215044231 - 215 = 153312215011463 is a prime.

It is a super-2 number, since 2×1533122150442312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (153312215044237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76656107522115 + 76656107522116.

It is an arithmetic number, because the mean of its divisors is an integer number (76656107522116).

Almost surely, 2153312215044231 is an apocalyptic number.

153312215044231 is a deficient number, since it is larger than the sum of its proper divisors (1).

153312215044231 is an equidigital number, since it uses as much as digits as its factorization.

153312215044231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 153312215044231 its reverse (132440512213351), we get a palindrome (285752727257582).

The spelling of 153312215044231 in words is "one hundred fifty-three trillion, three hundred twelve billion, two hundred fifteen million, forty-four thousand, two hundred thirty-one".