Base | Representation |
---|---|
bin | 10110010011110101101… |
… | …110101001100001011001 |
3 | 12102120021112110112010112 |
4 | 112103311232221201121 |
5 | 200104323014111433 |
6 | 3132151034054105 |
7 | 215523262341641 |
oct | 26236556514131 |
9 | 5376245415115 |
10 | 1533131003993 |
11 | 541219535026 |
12 | 20916a57a335 |
13 | b175c370694 |
14 | 542bd85d521 |
15 | 29d30ce3348 |
hex | 164f5ba9859 |
1533131003993 has 2 divisors, whose sum is σ = 1533131003994. Its totient is φ = 1533131003992.
The previous prime is 1533131003953. The next prime is 1533131004091. The reversal of 1533131003993 is 3993001313351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1516375513744 + 16755490249 = 1231412^2 + 129443^2 .
It is a cyclic number.
It is not a de Polignac number, because 1533131003993 - 28 = 1533131003737 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1533131003993.
It is not a weakly prime, because it can be changed into another prime (1533131003933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 766565501996 + 766565501997.
It is an arithmetic number, because the mean of its divisors is an integer number (766565501997).
Almost surely, 21533131003993 is an apocalyptic number.
It is an amenable number.
1533131003993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1533131003993 is an equidigital number, since it uses as much as digits as its factorization.
1533131003993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 98415, while the sum is 41.
The spelling of 1533131003993 in words is "one trillion, five hundred thirty-three billion, one hundred thirty-one million, three thousand, nine hundred ninety-three".
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