Base | Representation |
---|---|
bin | 10110010011110101101… |
… | …110101001100010111011 |
3 | 12102120021112110112021011 |
4 | 112103311232221202323 |
5 | 200104323014112331 |
6 | 3132151034054351 |
7 | 215523262342141 |
oct | 26236556514273 |
9 | 5376245415234 |
10 | 1533131004091 |
11 | 541219535105 |
12 | 20916a57a3b7 |
13 | b175c37073b |
14 | 542bd85d591 |
15 | 29d30ce33b1 |
hex | 164f5ba98bb |
1533131004091 has 2 divisors, whose sum is σ = 1533131004092. Its totient is φ = 1533131004090.
The previous prime is 1533131003993. The next prime is 1533131004113. The reversal of 1533131004091 is 1904001313351.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1533131004091 - 211 = 1533131002043 is a prime.
It is not a weakly prime, because it can be changed into another prime (1533131004191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 766565502045 + 766565502046.
It is an arithmetic number, because the mean of its divisors is an integer number (766565502046).
Almost surely, 21533131004091 is an apocalyptic number.
1533131004091 is a deficient number, since it is larger than the sum of its proper divisors (1).
1533131004091 is an equidigital number, since it uses as much as digits as its factorization.
1533131004091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 31.
The spelling of 1533131004091 in words is "one trillion, five hundred thirty-three billion, one hundred thirty-one million, four thousand, ninety-one".
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