Base | Representation |
---|---|
bin | 1000111011001101001… |
… | …1010100000101101001 |
3 | 112122202222021200111222 |
4 | 2032303103110011221 |
5 | 10003011000240131 |
6 | 154234553431425 |
7 | 14035465556465 |
oct | 2166323240551 |
9 | 478688250458 |
10 | 153332040041 |
11 | 5a033a37154 |
12 | 2587270b575 |
13 | 115c799c19b |
14 | 75c810b4a5 |
15 | 3ec63b087b |
hex | 23b34d4169 |
153332040041 has 2 divisors, whose sum is σ = 153332040042. Its totient is φ = 153332040040.
The previous prime is 153332040013. The next prime is 153332040047. The reversal of 153332040041 is 140040233351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111315649600 + 42016390441 = 333640^2 + 204979^2 .
It is a cyclic number.
It is not a de Polignac number, because 153332040041 - 234 = 136152170857 is a prime.
It is a super-3 number, since 3×1533320400413 (a number of 35 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (153332040047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76666020020 + 76666020021.
It is an arithmetic number, because the mean of its divisors is an integer number (76666020021).
Almost surely, 2153332040041 is an apocalyptic number.
It is an amenable number.
153332040041 is a deficient number, since it is larger than the sum of its proper divisors (1).
153332040041 is an equidigital number, since it uses as much as digits as its factorization.
153332040041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 153332040041 its reverse (140040233351), we get a palindrome (293372273392).
The spelling of 153332040041 in words is "one hundred fifty-three billion, three hundred thirty-two million, forty thousand, forty-one".
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