Base | Representation |
---|---|
bin | 1000111011001101001… |
… | …1010100000101101111 |
3 | 112122202222021200112012 |
4 | 2032303103110011233 |
5 | 10003011000240142 |
6 | 154234553431435 |
7 | 14035465556504 |
oct | 2166323240557 |
9 | 478688250465 |
10 | 153332040047 |
11 | 5a033a3715a |
12 | 2587270b57b |
13 | 115c799c1a4 |
14 | 75c810b4ab |
15 | 3ec63b0882 |
hex | 23b34d416f |
153332040047 has 2 divisors, whose sum is σ = 153332040048. Its totient is φ = 153332040046.
The previous prime is 153332040041. The next prime is 153332040053. The reversal of 153332040047 is 740040233351.
It is a balanced prime because it is at equal distance from previous prime (153332040041) and next prime (153332040053).
It is a cyclic number.
It is not a de Polignac number, because 153332040047 - 218 = 153331777903 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 153332039995 and 153332040022.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (153332040041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76666020023 + 76666020024.
It is an arithmetic number, because the mean of its divisors is an integer number (76666020024).
Almost surely, 2153332040047 is an apocalyptic number.
153332040047 is a deficient number, since it is larger than the sum of its proper divisors (1).
153332040047 is an equidigital number, since it uses as much as digits as its factorization.
153332040047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 32.
Adding to 153332040047 its reverse (740040233351), we get a palindrome (893372273398).
The spelling of 153332040047 in words is "one hundred fifty-three billion, three hundred thirty-two million, forty thousand, forty-seven".
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