Base | Representation |
---|---|
bin | 10110010100001100100… |
… | …001100000011110101110 |
3 | 12102121021012002000220220 |
4 | 112110030201200132232 |
5 | 200111113414410204 |
6 | 3132253014552210 |
7 | 215535615061206 |
oct | 26241441403656 |
9 | 5377235060826 |
10 | 1533513435054 |
11 | 5413a53a0157 |
12 | 209256668666 |
13 | b17c0670253 |
14 | 5431856d406 |
15 | 29d546861d9 |
hex | 1650c8607ae |
1533513435054 has 24 divisors (see below), whose sum is σ = 3073445975400. Its totient is φ = 510103523952.
The previous prime is 1533513435053. The next prime is 1533513435059. The reversal of 1533513435054 is 4505343153351.
It is a super-2 number, since 2×15335134350542 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1533513434997 and 1533513435015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1533513435053) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 819672 + ... + 1933620.
It is an arithmetic number, because the mean of its divisors is an integer number (128060248975).
Almost surely, 21533513435054 is an apocalyptic number.
1533513435054 is an abundant number, since it is smaller than the sum of its proper divisors (1539932540346).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1533513435054 is an equidigital number, since it uses as much as digits as its factorization.
1533513435054 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1114912 (or 1114433 counting only the distinct ones).
The product of its (nonzero) digits is 810000, while the sum is 42.
The spelling of 1533513435054 in words is "one trillion, five hundred thirty-three billion, five hundred thirteen million, four hundred thirty-five thousand, fifty-four".
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