Base | Representation |
---|---|
bin | 10110010100001110101… |
… | …110001110000111010100 |
3 | 12102121100202111002110222 |
4 | 112110032232032013110 |
5 | 200111202340302012 |
6 | 3132300413333512 |
7 | 215536543442543 |
oct | 26241656160724 |
9 | 5377322432428 |
10 | 1533550322132 |
11 | 5414141a4a44 |
12 | 209266a97298 |
13 | b17c81b6c1a |
14 | 5431d41215a |
15 | 29d57a20972 |
hex | 1650eb8e1d4 |
1533550322132 has 24 divisors (see below), whose sum is σ = 2695356464640. Its totient is φ = 763451136000.
The previous prime is 1533550322089. The next prime is 1533550322201. The reversal of 1533550322132 is 2312230553351.
It is a super-2 number, since 2×15335503221322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1533550322092 and 1533550322101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1982669 + ... + 2645387.
It is an arithmetic number, because the mean of its divisors is an integer number (112306519360).
Almost surely, 21533550322132 is an apocalyptic number.
It is an amenable number.
1533550322132 is a deficient number, since it is larger than the sum of its proper divisors (1161806142508).
1533550322132 is a wasteful number, since it uses less digits than its factorization.
1533550322132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 665231 (or 665229 counting only the distinct ones).
The product of its (nonzero) digits is 81000, while the sum is 35.
Adding to 1533550322132 its reverse (2312230553351), we get a palindrome (3845780875483).
The spelling of 1533550322132 in words is "one trillion, five hundred thirty-three billion, five hundred fifty million, three hundred twenty-two thousand, one hundred thirty-two".
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