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153400342013447 is a prime number
BaseRepresentation
bin100010111000010001001100…
…111001001110011000000111
3202010010221002120212112010012
4202320101030321032120013
5130101302400023412242
61302131051054220435
744211544323033314
oct4270211471163007
9663127076775105
10153400342013447
11449727a0a23081
12152560201b471b
136779789825069
1429c488aaa3d0b
1512b04655c9282
hex8b844ce4e607

153400342013447 has 2 divisors, whose sum is σ = 153400342013448. Its totient is φ = 153400342013446.

The previous prime is 153400342013441. The next prime is 153400342013543. The reversal of 153400342013447 is 744310243004351.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 153400342013447 - 24 = 153400342013431 is a prime.

It is a super-3 number, since 3×1534003420134473 (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (153400342013441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76700171006723 + 76700171006724.

It is an arithmetic number, because the mean of its divisors is an integer number (76700171006724).

Almost surely, 2153400342013447 is an apocalyptic number.

153400342013447 is a deficient number, since it is larger than the sum of its proper divisors (1).

153400342013447 is an equidigital number, since it uses as much as digits as its factorization.

153400342013447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 483840, while the sum is 41.

Adding to 153400342013447 its reverse (744310243004351), we get a palindrome (897710585017798).

The spelling of 153400342013447 in words is "one hundred fifty-three trillion, four hundred billion, three hundred forty-two million, thirteen thousand, four hundred forty-seven".