Base | Representation |
---|---|
bin | 100010111000010010001100… |
… | …110111010011110001101110 |
3 | 202010011000212101100202011001 |
4 | 202320102030313103301232 |
5 | 130101312044301044402 |
6 | 1302131345353350514 |
7 | 44211613034313022 |
oct | 4270221467236156 |
9 | 663130771322131 |
10 | 153401415253102 |
11 | 449731a181a9a5 |
12 | 1525627b70843a |
13 | 67798cac96503 |
14 | 29c494d438382 |
15 | 12b04c9926187 |
hex | 8b848cdd3c6e |
153401415253102 has 4 divisors (see below), whose sum is σ = 230102122879656. Its totient is φ = 76700707626550.
The previous prime is 153401415253057. The next prime is 153401415253159. The reversal of 153401415253102 is 201352514104351.
153401415253102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38350353813274 + ... + 38350353813277.
It is an arithmetic number, because the mean of its divisors is an integer number (57525530719914).
Almost surely, 2153401415253102 is an apocalyptic number.
153401415253102 is a deficient number, since it is larger than the sum of its proper divisors (76700707626554).
153401415253102 is an equidigital number, since it uses as much as digits as its factorization.
153401415253102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76700707626553.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 153401415253102 its reverse (201352514104351), we get a palindrome (354753929357453).
The spelling of 153401415253102 in words is "one hundred fifty-three trillion, four hundred one billion, four hundred fifteen million, two hundred fifty-three thousand, one hundred two".
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