Base | Representation |
---|---|
bin | 100010111000010010001100… |
… | …110111010011110010100111 |
3 | 202010011000212101100202020011 |
4 | 202320102030313103302213 |
5 | 130101312044301100114 |
6 | 1302131345353351051 |
7 | 44211613034313133 |
oct | 4270221467236247 |
9 | 663130771322204 |
10 | 153401415253159 |
11 | 449731a181aa47 |
12 | 1525627b708487 |
13 | 67798cac96548 |
14 | 29c494d4383c3 |
15 | 12b04c99261c4 |
hex | 8b848cdd3ca7 |
153401415253159 has 2 divisors, whose sum is σ = 153401415253160. Its totient is φ = 153401415253158.
The previous prime is 153401415253057. The next prime is 153401415253189. The reversal of 153401415253159 is 951352514104351.
It is a happy number.
153401415253159 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (951352514104351) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 153401415253159 - 211 = 153401415251111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (153401415253189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76700707626579 + 76700707626580.
It is an arithmetic number, because the mean of its divisors is an integer number (76700707626580).
Almost surely, 2153401415253159 is an apocalyptic number.
153401415253159 is a deficient number, since it is larger than the sum of its proper divisors (1).
153401415253159 is an equidigital number, since it uses as much as digits as its factorization.
153401415253159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620000, while the sum is 49.
The spelling of 153401415253159 in words is "one hundred fifty-three trillion, four hundred one billion, four hundred fifteen million, two hundred fifty-three thousand, one hundred fifty-nine".
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