1534111431137 has 2 divisors, whose sum is σ = 1534111431138. Its totient is φ = 1534111431136.

The previous prime is 1534111431101. The next prime is 1534111431143. The reversal of 1534111431137 is 7311341114351.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1389795778816 + 144315652321 = 1178896^2 + 379889^2 .

It is an emirp because it is prime and its reverse (7311341114351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1534111431137 - 2¹² = 1534111427041 is a prime.

It is a super-3 number, since 3×1534111431137³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1534111431097 and 1534111431106.

It is not a weakly prime, because it can be changed into another prime (1534111431197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 767055715568 + 767055715569.

It is an arithmetic number, because the mean of its divisors is an integer number (767055715569).

Almost surely, 2^{1534111431137} is an apocalyptic number.

It is an amenable number.

1534111431137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1534111431137 is an equidigital number, since it uses as much as digits as its factorization.

1534111431137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15120, while the sum is 35.

Adding to 1534111431137 its reverse (7311341114351), we get a palindrome (8845452545488).

The spelling of 1534111431137 in words is "one trillion, five hundred thirty-four billion, one hundred eleven million, four hundred thirty-one thousand, one hundred thirty-seven".