Base | Representation |
---|---|
bin | 11100100100111010… |
… | …01000101011000001 |
3 | 1110121012201000111012 |
4 | 32102131020223001 |
5 | 222410023404441 |
6 | 11014212330305 |
7 | 1052121650141 |
oct | 162235105301 |
9 | 43535630435 |
10 | 15342013121 |
11 | 6563191596 |
12 | 2b82013995 |
13 | 15a6666a96 |
14 | a57812921 |
15 | 5ebd719eb |
hex | 392748ac1 |
15342013121 has 2 divisors, whose sum is σ = 15342013122. Its totient is φ = 15342013120.
The previous prime is 15342013079. The next prime is 15342013123. The reversal of 15342013121 is 12131024351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8237377600 + 7104635521 = 90760^2 + 84289^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15342013121 is a prime.
Together with 15342013123, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (15342013123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7671006560 + 7671006561.
It is an arithmetic number, because the mean of its divisors is an integer number (7671006561).
Almost surely, 215342013121 is an apocalyptic number.
It is an amenable number.
15342013121 is a deficient number, since it is larger than the sum of its proper divisors (1).
15342013121 is an equidigital number, since it uses as much as digits as its factorization.
15342013121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 15342013121 its reverse (12131024351), we get a palindrome (27473037472).
The spelling of 15342013121 in words is "fifteen billion, three hundred forty-two million, thirteen thousand, one hundred twenty-one".
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