Base | Representation |
---|---|
bin | 1101111101000010111111… |
… | …0010101111100100110011 |
3 | 2000022201110222102100022002 |
4 | 3133100233302233210303 |
5 | 4002332241300400111 |
6 | 52344113542004215 |
7 | 3142311410603231 |
oct | 337205762574463 |
9 | 60281428370262 |
10 | 15342425012531 |
11 | 498575aa41701 |
12 | 187956b11666b |
13 | 873a276363a6 |
14 | 3b08122b5951 |
15 | 1b915967263b |
hex | df42fcaf933 |
15342425012531 has 2 divisors, whose sum is σ = 15342425012532. Its totient is φ = 15342425012530.
The previous prime is 15342425012459. The next prime is 15342425012557. The reversal of 15342425012531 is 13521052424351.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 15342425012531 - 222 = 15342420818227 is a prime.
It is a super-2 number, since 2×153424250125312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15342425012591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7671212506265 + 7671212506266.
It is an arithmetic number, because the mean of its divisors is an integer number (7671212506266).
Almost surely, 215342425012531 is an apocalyptic number.
15342425012531 is a deficient number, since it is larger than the sum of its proper divisors (1).
15342425012531 is an equidigital number, since it uses as much as digits as its factorization.
15342425012531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 15342425012531 its reverse (13521052424351), we get a palindrome (28863477436882).
The spelling of 15342425012531 in words is "fifteen trillion, three hundred forty-two billion, four hundred twenty-five million, twelve thousand, five hundred thirty-one".
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