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153432243431 is a prime number
BaseRepresentation
bin1000111011100101000…
…1100011110011100111
3112200000221211112201122
42032321101203303213
510003212123242211
6154252533244155
714041123356605
oct2167121436347
9480027745648
10153432243431
115a085557475
12258a019365b
131161268442c
1475d7552875
153ed00a56db
hex23b9463ce7

153432243431 has 2 divisors, whose sum is σ = 153432243432. Its totient is φ = 153432243430.

The previous prime is 153432243383. The next prime is 153432243439. The reversal of 153432243431 is 134342234351.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-153432243431 is a prime.

It is a super-2 number, since 2×1534322434312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 153432243391 and 153432243400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (153432243439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76716121715 + 76716121716.

It is an arithmetic number, because the mean of its divisors is an integer number (76716121716).

Almost surely, 2153432243431 is an apocalyptic number.

153432243431 is a deficient number, since it is larger than the sum of its proper divisors (1).

153432243431 is an equidigital number, since it uses as much as digits as its factorization.

153432243431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 103680, while the sum is 35.

Adding to 153432243431 its reverse (134342234351), we get a palindrome (287774477782).

The spelling of 153432243431 in words is "one hundred fifty-three billion, four hundred thirty-two million, two hundred forty-three thousand, four hundred thirty-one".