Base | Representation |
---|---|
bin | 10110010101000011110… |
… | …111101111100111011111 |
3 | 12102200122220100120210102 |
4 | 112111003313233213133 |
5 | 200120014123323403 |
6 | 3132525105331315 |
7 | 215600621615051 |
oct | 26250367574737 |
9 | 5380586316712 |
10 | 1534442011103 |
11 | 541831570081 |
12 | 209475636b3b |
13 | b190ab60731 |
14 | 543a5a078d1 |
15 | 29daae59b88 |
hex | 16543def9df |
1534442011103 has 2 divisors, whose sum is σ = 1534442011104. Its totient is φ = 1534442011102.
The previous prime is 1534442011079. The next prime is 1534442011133. The reversal of 1534442011103 is 3011102444351.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1534442011103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1534442011133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 767221005551 + 767221005552.
It is an arithmetic number, because the mean of its divisors is an integer number (767221005552).
Almost surely, 21534442011103 is an apocalyptic number.
1534442011103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1534442011103 is an equidigital number, since it uses as much as digits as its factorization.
1534442011103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 1534442011103 its reverse (3011102444351), we get a palindrome (4545544455454).
The spelling of 1534442011103 in words is "one trillion, five hundred thirty-four billion, four hundred forty-two million, eleven thousand, one hundred three".
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