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15345000315143 is a prime number
BaseRepresentation
bin1101111101001100100101…
…0010101111100100000111
32000022222010110022021100022
43133103021102233210013
54002403030040041033
652345221255405355
73142432261402142
oct337231122574407
960288113267308
1015345000315143
1149868616a8674
121879b6968385b
1387404803caa5
143b09b8329059
151b925a7c5098
hexdf4c94af907

15345000315143 has 2 divisors, whose sum is σ = 15345000315144. Its totient is φ = 15345000315142.

The previous prime is 15345000315091. The next prime is 15345000315157. The reversal of 15345000315143 is 34151300054351.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 15345000315143 - 220 = 15344999266567 is a prime.

It is a super-2 number, since 2×153450003151432 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15345000315343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7672500157571 + 7672500157572.

It is an arithmetic number, because the mean of its divisors is an integer number (7672500157572).

Almost surely, 215345000315143 is an apocalyptic number.

15345000315143 is a deficient number, since it is larger than the sum of its proper divisors (1).

15345000315143 is an equidigital number, since it uses as much as digits as its factorization.

15345000315143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 15345000315143 its reverse (34151300054351), we get a palindrome (49496300369494).

The spelling of 15345000315143 in words is "fifteen trillion, three hundred forty-five billion, three hundred fifteen thousand, one hundred forty-three".