153500131 has 2 divisors, whose sum is σ = 153500132. Its totient is φ = 153500130.

The previous prime is 153500129. The next prime is 153500141. The reversal of 153500131 is 131005351.

153500131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (131005351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 153500131 - 2¹ = 153500129 is a prime.

It is a super-2 number, since 2×153500131² = 47124580434034322, which contains 22 as substring.

Together with 153500129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 153500099 and 153500108.

It is not a weakly prime, because it can be changed into another prime (153500111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76750065 + 76750066.

It is an arithmetic number, because the mean of its divisors is an integer number (76750066).

Almost surely, 2^153500131 is an apocalyptic number.

153500131 is a deficient number, since it is larger than the sum of its proper divisors (1).

153500131 is an equidigital number, since it uses as much as digits as its factorization.

153500131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 153500131 is about 12389.5169800925. The cubic root of 153500131 is about 535.4302661523.

Adding to 153500131 its reverse (131005351), we get a palindrome (284505482).

The spelling of 153500131 in words is "one hundred fifty-three million, five hundred thousand, one hundred thirty-one".