Base | Representation |
---|---|
bin | 1000111011110101010… |
… | …1111011110011000001 |
3 | 112200012201021021221202 |
4 | 2032331111323303001 |
5 | 10003332111433022 |
6 | 154303412230545 |
7 | 14042612500046 |
oct | 2167525736301 |
9 | 480181237852 |
10 | 153500499137 |
11 | 5a110036a47 |
12 | 258bb00b455 |
13 | 1162386201b |
14 | 760263d1cd |
15 | 3ed6089592 |
hex | 23bd57bcc1 |
153500499137 has 2 divisors, whose sum is σ = 153500499138. Its totient is φ = 153500499136.
The previous prime is 153500499127. The next prime is 153500499211. The reversal of 153500499137 is 731994005351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 149621202481 + 3879296656 = 386809^2 + 62284^2 .
It is a cyclic number.
It is not a de Polignac number, because 153500499137 - 24 = 153500499121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 153500499091 and 153500499100.
It is not a weakly prime, because it can be changed into another prime (153500499127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76750249568 + 76750249569.
It is an arithmetic number, because the mean of its divisors is an integer number (76750249569).
Almost surely, 2153500499137 is an apocalyptic number.
It is an amenable number.
153500499137 is a deficient number, since it is larger than the sum of its proper divisors (1).
153500499137 is an equidigital number, since it uses as much as digits as its factorization.
153500499137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 510300, while the sum is 47.
The spelling of 153500499137 in words is "one hundred fifty-three billion, five hundred million, four hundred ninety-nine thousand, one hundred thirty-seven".
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