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153512142224393 is a prime number
BaseRepresentation
bin100010111001111001010100…
…101101001011110000001001
3202010112121200010200200122202
4202321321110231023300021
5130110120331402140033
61302254300552525545
744222612664120221
oct4271712455136011
9663477603620582
10153512142224393
1144a06152261327
12152738219b08b5
136787195c87034
1429ca054db7081
1512b330a76c8e8
hex8b9e54b4bc09

153512142224393 has 2 divisors, whose sum is σ = 153512142224394. Its totient is φ = 153512142224392.

The previous prime is 153512142224387. The next prime is 153512142224431. The reversal of 153512142224393 is 393422241215351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 151682082501184 + 1830059723209 = 12315928^2 + 1352797^2 .

It is an emirp because it is prime and its reverse (393422241215351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 153512142224393 - 210 = 153512142223369 is a prime.

It is not a weakly prime, because it can be changed into another prime (153512142224293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76756071112196 + 76756071112197.

It is an arithmetic number, because the mean of its divisors is an integer number (76756071112197).

Almost surely, 2153512142224393 is an apocalyptic number.

It is an amenable number.

153512142224393 is a deficient number, since it is larger than the sum of its proper divisors (1).

153512142224393 is an equidigital number, since it uses as much as digits as its factorization.

153512142224393 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1555200, while the sum is 47.

The spelling of 153512142224393 in words is "one hundred fifty-three trillion, five hundred twelve billion, one hundred forty-two million, two hundred twenty-four thousand, three hundred ninety-three".