Base | Representation |
---|---|
bin | 1000111100011011101… |
… | …0010110011011100001 |
3 | 112200121220100122002201 |
4 | 2033012322112123201 |
5 | 10004144211242403 |
6 | 154331345213201 |
7 | 14046602202202 |
oct | 2170672263341 |
9 | 480556318081 |
10 | 153661040353 |
11 | 5a192718a37 |
12 | 25944931201 |
13 | 1164abb1c22 |
14 | 7619aad5a9 |
15 | 3ee51ec21d |
hex | 23c6e966e1 |
153661040353 has 2 divisors, whose sum is σ = 153661040354. Its totient is φ = 153661040352.
The previous prime is 153661040333. The next prime is 153661040369. The reversal of 153661040353 is 353040166351.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 80970409809 + 72690630544 = 284553^2 + 269612^2 .
It is a cyclic number.
It is not a de Polignac number, because 153661040353 - 229 = 153124169441 is a prime.
It is a super-2 number, since 2×1536610403532 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (153661040333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76830520176 + 76830520177.
It is an arithmetic number, because the mean of its divisors is an integer number (76830520177).
Almost surely, 2153661040353 is an apocalyptic number.
It is an amenable number.
153661040353 is a deficient number, since it is larger than the sum of its proper divisors (1).
153661040353 is an equidigital number, since it uses as much as digits as its factorization.
153661040353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 37.
The spelling of 153661040353 in words is "one hundred fifty-three billion, six hundred sixty-one million, forty thousand, three hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •